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Derivative Rules

Last Updated : 10 Jun, 2025
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Derivative Rules are a set of rules that need to be followed while differentiating different functions. Rules of Derivatives are also called Differentiation Rules. Differentiation or derivatives is a method of finding the change in a value to another value.

Derivative helps us find the instantaneous rate of change of a quantity at a specific point. Some functions can be differentiated directly, but in certain cases, we use the rules of derivatives to find the derivative of a function. These rules of derivatives help us to solve the problem easily and efficiently.

In this article, we shall discuss the Rules of Derivatives in detail.

What are the Rules of Derivatives?

We have learned to express the mathematical writing of differentiating a function f(x) with respect to x as:

f'(x) = d(f(x))/dx

where d/dx represents the differentiation and f'(x) is the function after differentiation.

In some conditions, the given function f(x) may not be a simple function but a special function or a compound function. In this case, we need to use the rules of derivatives to solve them.

There are different rules of derivatives, which are as follows:

Different Rules of Derivatives

We will study the following rules of derivatives:

Power Rule of Derivative

Power rule of differentiation says that if the given function is of the form xn ,where n is any constant, then we can differentiate the function in the following way:

f(x) = xn

f'(x) = d((xn))/dx

f'(x) = nxn-1

This means that in such a case the differentiation is equal to the variable raised to 1 less than the original power and multiplied by the original power. Or, simply the power will be dropped in front of variable(i.e x in this case) and the power is reduced by one.

Let us understand it with an example.

Example: Differentiate the function f(x) = x3 with respect to x.

Given f(x) = x3
⇒ f'(x) = d/dx(x3)
⇒ f'(x) = 3x3-1
⇒ f'(x) = 3x2

Product Rule of Derivative

Product rule of differentiation states that if the function f(x) can be written as the product of two functions, g(x) and h(x), then the derivative of f(x) is found by:

f(x) = g(x).h(x)

f'(x) = g'(x)h(x) + g(x)h'(x)

If there is two subfunctions in the main function then, we need to do derivative twice, taking one function constantn at a time. In above demo, f(x) is the main function and g(x) and h(x) are it's two subfunction. so, in the derivate first h(x) is taken as constant and g(x) is differentiated to g'(x). Similarly in the second part g(x) is taken as constant and h(x) is differentiated to h'(x).

Let us understand it with an example.

Example: Differentiate the function f(x) = (x+1)(x+2) with respect to x.

Given f(x) = (x+1)(x+2)

As the given function is a product of two functions g(x) = x+1 and h(x) = x+2, we can find the derivative of f(x) as:

f(x) = g(x).h(x)

⇒ f'(x) = g'(x)h(x) + g(x)h'(x)

⇒ f′(x) = (x+2).d/d​x(x+1) + (x+1).d/d​x(x+2)

⇒ f'(x) = (x+2) + (x+1)

⇒ f'(x) = 2x + 3

Quotient Rule of Derivative

Quotient rule of differentiation says that if the function f(x) can be written as the quotient of two functions, g(x) and h(x), then the derivative of f(x) is calculated as follows:

f(x) = \frac{g(x)}{h(x)}\\\Rightarrow f'(x) = \frac{g'(x)h(x) - g(x)h'(x)}{(h(x))^2}

Let us understand it with an example.

Example: Differentiate the function f(x) = \frac{(x+1)}{(x+2)} with respect to x.

Given f(x) = (x+1)(x+2)

As the given function is a product of two functions g(x) = x+1 and h(x) = x+2, we can find the derivative of f(x) as:

f(x) = \frac{g(x)}{h(x)}\\ \Rightarrow f'(x) = \frac{g'(x)h(x) - g(x)h'(x)}{(h(x))^2}\\ \Rightarrow f'(x) = \frac{(x+2).\frac{d}{dx}(x+1) - (x+1).\frac{d}{dx}(x+2)}{(x+2)^2}\\ \Rightarrow f'(x) = \frac{x+2 - (x+1) }{(x+2)^2}\\ \Rightarrow f'(x) = \frac{1}{(x+2)^2}

Chain Rule of Derivative

Chain rule of differentiation states that if a function y = f(x) = g(t), where t = h(x), then differentiating f(x) can be done as follows:

f(x) = g(t)

⇒ f(x) = g(h(x))

⇒ f′(x) = d/d​x(g(h(x))

⇒ f'(x) = g'(h(x)).h'(x)

Let us understand it with an example.

Example: Differentiate the function f(x) = sin(x2) with respect to x.

Given f(x) = sin(x2)

We can consider g(t) = sin (t) and h(x) = x2

Thus f(x) = g(h(x))

Using chain rule,

f'(x) = g'(h(x)).h'(x), and

g'(t) = d/dt(sin t) = cos t

⇒ g'(x) = cos x

⇒ h'(t) = d/dt(t2) = 2t

⇒ h'(x) = 2x

⇒ f'(x) = cos(x2).2x = 2x.cos(x2)

Sum and Difference Rule of Derivative

If a function f(x) is the sum or difference of two functions, g(x) and h(x), then the derivative of f(x) is equal to the sum or difference of the derivatives of g(x) and h(x). Mathematically, it can be written as:

For a function f such that,

f(x) = g(x) ± h(x)

⇒ d/dx(f(x)) = d/dx{g(x) ± h(x)}

⇒ d/dx(f(x)) = d/dx{g(x)} ± d/dx{h(x)}

⇒ f'(x) = g'(x) ± h'(x)

Let us understand it with an example.

Example: Find the derivative of f(x) = sin(x) + cos(x) with respect to x.

Given f(x) = sin(x) + cos(x)

Let g(x) = sin(x) and h(x) = cos(x)

As f(x) = g(x) + h(x)

⇒ f'(x) = g'(x) + h'(x)

f'(x) = \frac{d}{dx}(\sin x)+ \frac{d}{dx}(\cos x)

⇒ f'(x) = cos x - sin x

Derivative Rules for Constant Multiple

This rule of differentiation says that if a function is multiplied by a constant, the constant remains the same during differentiation and can be taken out of the derivative. Thus, if we have a function f(x) and it is multiplied by any constant 'a', then

d/dx{a.f(x)} = a.d/dx{f(x)} = a.f'(x)

Let us understand it with an example.

Example: Calculate the derivative of f(x) = 3x3.

Solution:

f(x) = 3x3

⇒ f'(x) = d/dx(3x3)

⇒ f'(x) = 3.d/dx(x3)

⇒ f'(x) = 3(3x2) = 9x2

Derivative Rules for Various Functions

In this section, we will discuss the rules of differentiation for the below listed functions:

Derivative Rules for Trigonometric Function

Trigonometry makes use of 6 functions which are sin, cos, tan, sec, cosec and cot. The derivatives of these 6 functions is given below:

f(x)f'(x)
sin(x)cos(x)
cos(x)-sin(x)
tan(x)sec2x
sec(x)sec(x)tan(x)
cosec(x)-cosec(x)cot(x)
cot(x)-cosec2x

Derivative Rules for Inverse Trigonometric Function

Trigonometry also has 6 inverse functions which are sin-1, cos-1, tan-1, sec-1, cosec-1, and cot-1. The derivatives of these 6 functions is given below:

f(x)f'(x)
sin-1(x)1/√(1-x2)
cos-1(x)-1/√(1-x2)
tan-1(x)1/(1+x2)
sec-1(x)1/[x√(x2-1)] where x ≠ -1, 0, 1
cosec-1(x)-1/[x√(x2-1)] where x ≠ -1, 0, 1
cot-1(x)-1/(1+x2)

Derivative Rules for Exponential Function

Any function which has 'e' is said to be an exponential function. Generally, we have two types of exponential functions which are given in the table below along with their derivatives:

f(x)f'(x)
exex
axaxln(a)

Derivative Rules for Logarithmic Function

Any function which involves 'e' is said to be a Logarithmic function. Generally, we have two types of Logarithmic functions which are given in the table below along with their derivatives:

f(x)f'(x)
loga x1/(x ln(a)) or 1/(x loge a)
ln(x) or loge x1/x

Derivative Rules for Hyperbolic Function

Each trigonometric function has a corresponding hyperbolic function which is named by adding an 'h' after the name of a trigonometric function. Thus we have 6 hyperbolic functions which are given below along with their derivatives:

f(x)f'(x)
sinh(x)cosh(x)
cosh(x)sinh(x)
tanh(x)sech2(x)
sech(x)-sech(x)tanh(x)
cosech(x)-cosech(x)coth(x)
coth(x)-cosech2(x)

Derivative Rules for Inverse Hyperbolic Function

Each inverse trigonometric function has a corresponding inverse hyperbolic function which is named by adding an 'h' after the name of an inverse trigonometric function. Thus we have 6 inverse hyperbolic functions which are given below along with their derivatives:

f(x)f'(x)
sinh-1(x)1/√(1+x2)
cosh-1(x)1/√(x2-1)
tanh-1(x)1/(1-x2)
sech-1(x)-1/√x(1-x2)
cosech-1(x)-1/|x|√(1-x2)
coth-1(x)1/(1-x2)

Derivative Rules for Composite Function

If a function f(x) is of the form g(h(x)) then,

f'(x) = g'(h(x)).h'(x)

This is the same as the chain rule. Refer to the example of the chain rule to understand it.

Derivative Rules for Parametric Function

If we have two functions x(t) and y(t) then we calculate dy/dx as follows:

  • First, we calculate the derivative of x(t) with respect to t.
  • Then we calculate the derivative of y(t) with respect to t.
  • Divide the derivative of y(t) by x(t) to get dy/dx.

dy/dx = x'(t)/y'(t)

Let us understand it with an example.

Example: Calculate dy/dx if x(t) = sin(x) y(t) = x2.

x(t) = sin(x)

⇒ x'(t) = cos(x)

and y(t) = x2

⇒ y'(t) = 2x

Thus, dy/dx = 2x/cos(x) = 2x.sec(x)

Derivative Rules for Implicit Function

A function that comprises both dependent and independent variables is called an implicit function. In such cases, it may not be easy to change the function into an explicit function. For example, if we have a function in variables x and y, then it may not be possible to write the function as y = f(x). In such cases, we differentiate the function by separating the variables on two sides of the equality sign.

Consider a function x2 + y = 3. This function can be differentiated as follows:

Given: x2 + y = 3

Separating the variables on both sides of the equation, we get:

y = 3 - x2

Now differentiating both sides w.r.t x, we get:

dy/dx = 0 - 2x

dy/dx = -2x

Derivative Rules for Infinite Series

If we have a function y = f(x) = x^{x^{x^{\ldots\infty}}} then, derivative of f(x) is calculated as:

y = f(x) = x^{x^{x^{\ldots\infty}}} \\ y = x^y\\

Taking logarithm on both sides, we get:

log y = y.log x

Differentiating both sides with respect to x, we get:

\frac{1}{y}\frac{dy}{dx} = \frac{dy}{dx}\log x+y\frac{d}{dx}(\log x)\\ \frac{1}{y}\frac{dy}{dx} = \frac{dy}{dx}\log x + \frac{y}{x}\\ \frac{dy}{dx}(\frac{1}{y}-\log x) = \frac{y}{x}\\ \frac{dy}{dx}\frac{(1-y\log x)}{y} = \frac{y}{x}\\ \frac{dy}{dx} = \frac{y^2}{x(1-y\log x)}

Partial Derivative Rules

Partial Derivative is applicable to multivariable function in which the function is differentiated with respect to a particular variable and the other variables are treated as scalar multiple. Product, quotient, power and chain rule are applicable to the partial derivatives also in the same way as they are applicable to complete derivatives.

Consider two functions u = f(x, y) and v = g(x, y) to be functions of x and y. Then the rules of derivatives can be applied to it as follows:

Product Rule of Partial Derivative

If there is a function h(x, y) which is a product of u and v then:

\frac{\partial h}{\partial x} = \frac{\partial f}{\partial x}.g(x, y)+f(x, y)\frac{\partial g}{\partial x}\\ \frac{\partial h}{\partial y} = \frac{\partial f}{\partial y}.g(x, y)+f(x, y)\frac{\partial g}{\partial y}

Quotient Rule of Partial Derivative

If there is a function h(x, y) which is a division of u and v then:

h(x, y) = \frac{f(x, y)}{g(x,y)}\\ \frac{\partial h}{\partial x} = \frac{\frac{\partial f}{\partial x}.g(x, y)-f(x, y)\frac{\partial g}{\partial x}}{(g(x,y))^2}\\ \frac{\partial h}{\partial y} = \frac{\frac{\partial f}{\partial y}.g(x, y)-f(x, y)\frac{\partial g}{\partial y}}{(g(x,y))^2}

Power Rule of Partial Derivative

According to this rule, if h(x, y) is a power of any function f(x, y), then:

h(x, y) = [f(x,y)]n

\frac{\partial h}{\partial x} = n[f(x,y)]^{n-1}.\frac{\partial f}{\partial x}\\ \frac{\partial h}{\partial y} = n[f(x,y)]^{n-1}.\frac{\partial f}{\partial y}

Chain Rule of Partial Derivative

According to this rule, if u = f(x, y) and x = (s, t) and y = (s, t), then:

\frac{\partial u}{\partial s} = \frac{\partial u}{\partial x}.\frac{\partial x}{\partial s}+\frac{\partial u}{\partial y}.\frac{\partial y}{\partial s}\\ \frac{\partial u}{\partial t} = \frac{\partial u}{\partial x}.\frac{\partial x}{\partial t}+\frac{\partial u}{\partial y}.\frac{\partial y}{\partial t}

Also, Check

Solved Examples on Derivative Rules

Example 1. Find the derivative of f(x) = (x+2)(x-7).

Solution:

f(x) = (x+2) (x-7)

g(x) = x+2 and h(x) = x-7

Using product rule, we get

f'(x) = g'(x)h(x) + g(x)h'(x)

f'(x)= 1(x-7) + (x+2)(1)

f'(x) = x - 7 + x + 2

f'(x)= 2x -5

Example 2. Find the derivative of f(x) = sin(x)/x.

Solution:

f(x) = sin(x)/x

g(x) = sin(x) and h(x) = x

Using quotient rule,

f(x) = \frac{g(x)}{h(x)}\\ f'(x) = \frac{g'(x)h(x) - g(x)h'(x)}{(h(x))^2}\\ f'(x) = \frac{x\frac{d}{dx}(\sin x)-\sin(x)\frac{d}{dx}(x)}{x^2}\\ f'(x) = \frac{x\cos x- sinx}{x^2}

Example 3. Find the derivative of f(x) = sin(x).cos(x).

Solution:

f(x) = sin(x).cos(x)

g(x) = sin(x) and h(x) = cos(x)

Using product rule,

f'(x) = g'(x)h(x) + g(x)h'(x)

f'(x) = cos(x).cos(x) + sin(x)[-sin(x)]

f'(x) = cos2x - sin2x = cos(2x)

Example 4. Find the derivative of f(x) = sec(2x+3).

Solution:

Given f(x) = sec(2x+3)

g(t) = sec(t) and t = h(x) = 2x+3

Using chain rule,

g'(t) = sec(t)tan(t) or g(x) = sec(x)tan(x)

h'(x) = 2

f'(x) = g'(h(x)).h'(x)

f'(x) = sec(2x+3)tan(2x+2)*2 = 2sec(2x+3)tan(2x+3)

Example 5. Find the derivative of f(x) = x2 + x + 1.

Solution:

Given f(x) = x2 + x + 1

Using sum/ difference rule

f'(x) = d/dx(x2) + d/dx(x) + d/dx(1)

f'(x) = 2x + 1 + 0

Practice Problems on Derivative Rules

Problem 1. Find the derivative of (x2+4)/x+1.

Problem 2. Find the derivative of log(2x)/x.

Problem 3. Find the derivative of tan(sin(x)).

Problem 4. Find the derivative of 9x6 + 2x.

Problem 5. Find the derivative of sin(x) + 3x2 + log(x).cos(x).

Problem 6. Find the derivative of cos(x)+x.sin(x).

Problem 7. Find the derivative of x2.ln(2x+2).

Problem 8. Find the derivative of esin(2x+5).(1+x).

Problem 9. Find the derivative of cot(sin(x)).

Problem 10. Find the derivative of log(x+1/x-1).


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