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Differentiation Formulas

Last Updated : 26 Feb, 2025
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Differentiation Formulas: Differentiation allows us to analyze how a function changes over its domain. We define the process of finding the derivatives as differentiation. The derivative of any function ๐‘“(x) is represented as d/dx.๐‘“(x)

In this article, we will learn about various differentiation formulas for Trigonometric Functions, Inverse Trigonometric Functions, Logarithmic Functions, etc., and their detailed examples.

Differentiation Formulas

What is Differentiation?

Differentiation is defined as the rate of change of one quantity with respect to the other quantity.

For any function y = ๐‘“(x), if the input value changes from x to x+h, then the output changes to y = ๐‘“(x+h). The differentiation of ๐‘“(x) with respect to x is defined as the rate of change of y with respect to x. When the change in the input x is very small (denoted by h), the corresponding change in the output y is also small.

The derivative of ๐‘“(x) at x is given by the limit as h approaches 0:

dy/dx = limhโ†’0 {๐‘“(x+h) - ๐‘“(x)}/{(x+h) - x}

Mathematically,

dy/dx = ๐‘“'(x) = limhโ†’0 {๐‘“(x+h) - ๐‘“(x)}/h

This limit represents the instantaneous rate of change of y with respect to x, or the slope of the tangent line to the curve y = ๐‘“(x) at the point (x, ๐‘“(x)).

Read in Detail: Calculus in Maths

Differentiation formulas are used to find the differentiation of the various functions. The first principal formula states that, for any function ๐‘“(x) its derivative with respect to x is,

๐‘“'(x) = limhโ†’0 {๐‘“(x+h) - ๐‘“(x)}/h

Basic Differentiation Formulas

The differentiation formulas for some elementary functions are:

Function (y =)Differentiation Formula (dy/dx =)
c (constant)0
xn (power) nxn-1
ln x (logarithmic)1/x
ex(exponent) ex
ax (exponent)ax log a

Differentiation of Trigonometric Functions

Derivatives of the trigonometric functions are:

Function (y =)Derivative (dy/dx =)
sin xcos x
cos x-sin x
tan xsecยฒ x
sec xsec x ยท tan x
cosec x-cosec x ยท cot x
cot x-cosecยฒ x

Differentiation of Inverse Trigonometric Functions

The differentiation formulas for the Inverse trigonometric functions are:

Function (y =)Differentiation Formula (dy/dx =)
sinโปยน x1/โˆš(1 - xยฒ)
cosโปยน x-1/โˆš(1 - xยฒ)
tanโปยน x1/(1 + xยฒ)
secโปยน x1/(|x|ยทโˆš(xยฒ - 1))
cosecโปยน x-1/(|x|ยทโˆš(xยฒ - 1))
cotโปยน x-1/(1 + xยฒ)

Differentiation of Hyperbolic Functions

Let's discuss the Differentials of Hyperbolic functions.

Function (y =)Differentiation Formula (dy/dx =)
sinh xcosh x
cosh xsinh x
tanh xsechยฒ x
sech x-sech x ยท tanh x
cosech x-cosech x ยท coth x
coth x-cosechยฒ x

Differentiation Rules

Various rules of finding the derivative of functions have been given below:

RulesFunction Form (y =)Differentiation Formula (dy/dx =)
Sum Ruleu(x) ยฑ v(x)du/dx ยฑ dv/dx
Product Ruleu(x) ร— v(x)u dv/dx + v du/dx
Quotient Ruleu(x) รท v(x)(v du/dx - u dv/dx) / vยฒ
Chain Rulef(g(x))f'[g(x)] g'(x)
Constant Rulek f(x), k โ‰  0k d/dx f(x)

Differentiation of Special Functions

If we have two parametric functions x = ๐‘“(t), y = g(t), where t is the parameter, then the differentiation of parametric functions is as follows,

As dy/dt = g'(t) and dx/dt = ๐‘“'(t) then dy/dx is given by:

dy/dx = (dy/dt)/(dx/dt) = g'(t)/๐‘“'(t)

Implicit Differentiation

If y is related to x but can not conveniently expressed in the form y = ๐‘“(x) but can be expressed in the form ๐‘“(x,y) = 0, then we say that y is an implicit function of x. In the case of implicit function dy/dx can be found by following steps.

(a) Differentiate each term of ๐‘“(x, y) = 0 with respect to x.

(b) Collect the terms containing dy/dx on one side and the terms not involving dy/dx on the other side.

(c) Express dy/dx as a function of x or y or both.

Example: Find the differentiation of x2 + y2 + 4xy = 0

Solution:

x2 + y2 + 4xy = 0

Differentiating with respect to x,

2x + 2ydy/dx + 4(xdy/dx + y) = 0
โ‡’ 2x + 4y + 2dy/dx(y + 2x) = 0
โ‡’ x + 2y + dy/dx(y + 2x) = 0
โ‡’ dy/dx(y + 2x) = -(x + 2y)
โ‡’ dy/dx = -(x + 2y)/(y + 2x)

Higher Order Differentiation

Higher order differentiation is nothing, but the differentiation of a function more than one time suppose we have a function y = ๐‘“(x) then its differential in higher order is calculated as,

First Derivative = dy/dx = ๐‘“'(x)

Second Derivative = d2y/dx2 = ๐‘“''(x)

Third Derivative = d3y/dx3 = ๐‘“'''(x)

....
....

nth Derivative = dny/dxn = ๐‘“(n)(x)

This can be understood using the example added below,

Example: Find the second-order derivative of ๐‘“(x) = 4x4 + 3x3 + 2x2 + x + 1

Solution:

๐‘“(x) = 4x4 + 3x3 + 2x2 + x + 1

Differentiating with respect to x,

๐‘“'(x) = 4(4x3) + 3(3x2) + 2(2x) + 1 + 0
โ‡’ ๐‘“'(x) = 16x3 + 9x2 + 4x + 1

For second-order derivative differentiating with respect to x,

๐‘“''(x) = 16(3x2) + 9(2x) + 4 + 0
โ‡’ ๐‘“''(x) = 48x2 + 18x + 4

This is the required second-order derivative.

Articles Related to Differentiation Formulas:

Solved Examples of Differentiation Formulas

Let's solve some example problems on the rules of derivative.

Example 1: Find the differentiation of y = 4x3 + 7x2 + 11x + 12

Solution:

Given, y = 4x3 + 7x2 + 11x + 12

Differentiating with respect to x,

dy/dx = 4(3x2) + 7(2x) + 11(1) + 0

โ‡’ dy/dx = 12x2 + 14x + 11

This is the required differentiation

Example 2: Find the differentiation of y = cos(log x)

Solution:

Given, y = cos(log x)

Differentiating with respect to x,

dy/dx = d/dx{cos (log x)}

โ‡’ dy/dx = sin (log x).{d/dx(log x)}
โ‡’ dy/dx = sin (log x).(1/x)

This is the required differentiation

Example 3: Find the differentiation of y = tan (3x2 + 4x)

Solution:

Given, y = tan (3x2 + 4x)

Differentiating with respect to x,

dy/dx = 1/{1 + (3x2 + 4x)2}2 d/dx(3x2 + 4x)

โ‡’ dy/dx = 1/{1 + (3x2 + 4x)2}2 (6x + 4)
โ‡’ dy/dx = (6x + 4)/{1 + (3x2 + 4x)2}2 

This is the required differentiation

Practice Problems on Differentiation Formulas

Problem 1: Find the derivative of the function f(x) = 3x2 + 5x - 2.

Problem 2: Determine the derivative of g(x) = 1/x.

Problem 3: Find the derivative of h(x) = \sqrt{x^3 + 2x - 1}.

Problem 4: Determine the derivative of y(x) = e2x.

Problem 5: Find the derivative of f(x) = \ln(x^2 + 3x).


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