Find the missing integer in an array if mean is given
Last Updated :
20 Feb, 2023
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Given an array of size N-1 and the mean of N elements (one element is not given). We need to find the missing value X in the array.
Examples:
Input : a[] = {2, 4, 20}, Mean = 9
Output : Missing Element = 10
Explanation : Mean of (2, 4, 20, 10) is (2 + 4 + 20 + 10)/4 = 9
Let x be the missing element Mean = (a1 + a2 + a3.. + X + ..an)/N. So (a1 + a2 + a3.. + X + ..aN) = Mean*N . Missing element x = (Mean*N - (a1 + a2 + a3....aN))
Implementation:
// C++ program to find missing element in a
// given array from mean.
#include <bits/stdc++.h>
using namespace std;
// Size of a[] is N - 1 (one element missing)
int findMissing(int a[], int N, int mean)
{
// Find sum of array elements
int sum = 0;
for (int i = 0; i < N - 1; i++)
sum += a[i];
return (mean * N) - sum;
}
int main() {
int a[] = {25, 65, 80};
int mean = 50;
int n = sizeof(a)/sizeof(a[0]);
cout << "The missing element : "
<< findMissing(a, n+1, mean) << endl;
return 0;
}
// Java program to find missing element
// in a given array from mean.
import java.io.*;
class GFG
{
// Size of a[] is N - 1 (one element missing)
public static int findMissing(int a[], int N, int mean)
{
// Find sum of array elements
int sum = 0;
for (int i = 0; i < N - 1; i++)
sum += a[i];
return (mean * N) - sum;
}
// Driver code
public static void main (String[] args)
{
int a[] = {25, 65, 80};
int mean = 50;
int n = a.length;
System.out.println("The missing element : "
+ findMissing(a, n + 1, mean));
}
}
// This code is contributed by upendra bartwal
# Python3 code to find missing element
# in a given array from mean.
# Size of a[] is N - 1
# (one element missing)
def findMissing( a , N , mean ):
# Find sum of array elements
sum = 0
for i in range(N - 1):
sum += a[i]
return (mean * N) - sum
# Driver Code
a = [25, 65, 80]
mean = 50
n = len(a)
print("The missing element : ", end = '')
print(findMissing(a, n+1, mean))
# This code is contributed by Sharad Bhardwaj.
// C# program to find missing element
// in a given array from mean.
using System;
class GFG {
// Size of a[] is N - 1
// (one element missing)
public static int findMissing(int[] a, int N, int mean)
{
// Find sum of array elements
int sum = 0;
for (int i = 0; i < N - 1; i++)
sum += a[i];
return (mean * N) - sum;
}
// Driver code
public static void Main()
{
int[] a = { 25, 65, 80 };
int mean = 50;
int n = a.Length;
Console.WriteLine("The missing element : "
+ findMissing(a, n + 1, mean));
}
}
// This code is contributed by vt_m.
<?php
// PHP program to find missing
// element in a given array
// from mean.
// Size of a[] is N - 1
// (one element missing)
function findMissing($a, $N, $mean)
{
// Find sum of array elements
$sum = 0;
for ($i = 0; $i < $N - 1; $i++)
$sum += $a[$i];
return ($mean * $N) - $sum;
}
// Driver Code
$a = array(25, 65, 80);
$mean = 50;
$n = count($a);
echo "The missing element : "
.findMissing($a, $n + 1, $mean);
// This code is contributed by Sam007
?>
<script>
// Javascript program to find
// missing element in a
// given array from mean.
// Size of a[] is N - 1
// (one element missing)
function findMissing( a, N, mean)
{
// Find sum of array elements
let sum = 0;
for (let i = 0; i < N - 1; i++)
sum += a[i];
return (mean * N) - sum;
}
// Driver Code
let a = [25, 65, 80];
let mean = 50;
let n = a.length;
document.write("The missing element : "
+ findMissing(a, n+1, mean) + "</br>");
</script>
Output
The missing element : 30
Time complexity: O(N) where N is no of the elements in the given array.
Auxiliary space: O(1) since constant space is required.