For the relation R(ABCDEFGH) with FD's= {CH->G, A->BC, B->CHF, E->A, F->EG such that F+ is exactly the set of FDs that hold for R.} Consider the FDs given in above question. The relation R is
in 1NF, but not in 2NF.
in 2NF, but not in 3NF.
in 3NF, but not in BCNF.
in BCNF