How to Make a Project Using Spring Boot, MySQL, Spring Data JPA, and Maven?
For the sample project, below mentioned tools got used
- Java 8
- Eclipse IDE for development
- Hibernate ORM, Spring framework with Spring Data JPA
- MySQL database, MySQL Connector Java as JDBC driver.
Example Project Using Spring Boot, MySQL, Spring Data JPA, and Maven
Project Structure:

As this is getting prepared as a maven project, all dependencies are specified in pom.xml
pom.xml
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0
http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.gfg</groupId>
<artifactId>SpringDataJPAConsoleSample</artifactId>
<version>0.0.1-SNAPSHOT</version>
<properties>
<maven.compiler.source>1.8</maven.compiler.source>
<maven.compiler.target>1.8</maven.compiler.target>
</properties>
<dependencies>
<!-- Spring framework with support for Spring Data JPA -->
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-context</artifactId>
<version>5.1.4.RELEASE</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-orm</artifactId>
<version>5.1.4.RELEASE</version>
</dependency>
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-core</artifactId>
<version>5.4.1.Final</version>
</dependency>
<dependency>
<groupId>org.springframework.data</groupId>
<artifactId>spring-data-jpa</artifactId>
<version>2.1.4.RELEASE</version>
</dependency>
<!-- Spring framework with support for Spring Data JPA -->
<!-- MySQL dependency -->
<dependency>
<groupId>mysql</groupId>
<artifactId>mysql-connector-java</artifactId>
<version>8.0.14</version>
</dependency>
</dependencies>
</project>
As we are connecting with MySQL, we need to create the database and table for use in the project
create database geeksforgeeks; # Creation use geeksforgeeks #Make the database active CREATE TABLE `Contest` ( `id` int(11) NOT NULL AUTO_INCREMENT, `contestName` varchar(45) NOT NULL, `contestDescription` varchar(45) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=utf8;
Database connection properties are set in src/main/resources/persistence.xml
persistence.xml
<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://xmlns.jcp.org/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence
http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd"
version="2.1">
<!-- Change the username and password with appropriate values -->
<persistence-unit name="GeeksDB">
<properties>
<property name="javax.persistence.jdbc.url" value="jdbc:mysql://localhost:3306/geeksforgeeks?useSSL=false" />
<property name="javax.persistence.jdbc.user" value="***" />
<property name="javax.persistence.jdbc.password" value="***" />
<property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver" />
<property name="hibernate.show_sql" value="true" />
<property name="hibernate.format_sql" value="true" />
</properties>
</persistence-unit>
</persistence>
Configuration of EntityManagerFactory and TransactionManager
ContestAppConfig.java
import javax.persistence.EntityManagerFactory;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.data.jpa.repository.config.EnableJpaRepositories;
import org.springframework.orm.jpa.JpaTransactionManager;
import org.springframework.orm.jpa.LocalEntityManagerFactoryBean;
@Configuration
// Scan the repositories that is present under com.gfg.jpa
@EnableJpaRepositories(basePackages = {"com.gfg.jpa"})
public class ContestAppConfig {
@Bean
// LocalEntityManagerFactoryBean sets up an EntityManagerFactory to work with GeeksDB
public LocalEntityManagerFactoryBean entityManagerFactory() {
LocalEntityManagerFactoryBean factoryBean = new LocalEntityManagerFactoryBean();
factoryBean.setPersistenceUnitName("GeeksDB");
return factoryBean;
}
@Bean
// Transaction manager for the configured EntityManagerFactory,
public JpaTransactionManager transactionManager(EntityManagerFactory entityManagerFactory) {
JpaTransactionManager transactionManager = new JpaTransactionManager();
transactionManager.setEntityManagerFactory(entityManagerFactory);
return transactionManager;
}
}
Let's implement the model class.
Contest.java
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
// It maps with db table Contest
@Entity
public class Contest {
// The @Id and @GeneratedValue annotations map
// the field id to the primary key column of the table.
// Suppose that all the fields of the class have
// same name as the column names in the database table.
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String contestName;
private String contestDescription;
protected Contest() {
}
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getContestName() {
return contestName;
}
public void setContestName(String contestName) {
this.contestName = contestName;
}
public String getContestDescription() {
return contestDescription;
}
public void setContestDescription(String contestDescription) {
this.contestDescription = contestDescription;
}
@Override
public String toString() {
return "Contest [contestName=" + contestName + ", contestDescription=" + contestDescription + "]";
}
}
ContestRepository.java
Instead of writing a generic DAO class, a simple interface like below is enough. It extends CrudRepository defined by Spring Data JPA. Common CRUD operations like save(), findAll(), findById(), delete(), count() etc., are defined by the interface.
import java.util.List;
import org.springframework.data.repository.CrudRepository;
public interface ContestRepository extends CrudRepository<Contest, Long> {
// We can add the required methods here
List<Contest> findByContestName(String contestName);
}
ContestService.java
import java.util.List;
import java.util.Optional;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Service;
@Service("contestService")
public class ContestService {
@Autowired
private ContestRepository contestRepository;
public void test() {
// Save a new contest
Contest geekContest = new Contest();
geekContest.setContestName("PremierLeague");
geekContest.setContestDescription("Inviting Geeks To submit articles in plenty");
contestRepository.save(geekContest);
// Find a contest by ID
Optional<Contest> result = contestRepository.findById(1L);
result.ifPresent(contest -> System.out.println(contest));
// Find contest by contest name
List<Contest> contests = contestRepository.findByContestName("PremierLeague");
contests.forEach(contest -> System.out.println(contest));
// List all contests
Iterable<Contest> iterator = contestRepository.findAll();
iterator.forEach(contest -> System.out.println(contest));
// Count number of contest
long countOfContest = contestRepository.count();
System.out.println("Number of contest held: " + countOfContest);
}
}
We can test the same via a test file
ContestTest.java
import org.springframework.context.annotation.AnnotationConfigApplicationContext;
public class ContestTest {
public static void main(String[] args) {
AnnotationConfigApplicationContext appContext = new AnnotationConfigApplicationContext();
appContext.scan("com.gfg.jpa");
appContext.refresh();
ContestService contestService = (ContestService) appContext.getBean("contestService");
contestService.test();
appContext.close();
}
}
We can run the test file as an ordinary Java application
Output:

As we have tested via contestname as well, in the first output, we saw that one contest got inserted and the same is getting used to test while testing via contestname

We can check the DB data also

Note: id field is auto-generated.