Python - Print Heart Pattern
Last Updated :
05 Aug, 2022
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Given an even integer input, the task is to write a Python program to print a heart using loops and mathematical formulations.
Example :
For n = 8
* * * *
* * *
* *
* G F G *
* *
* *
* *
*
For n = 14
* * * *
* * * *
* * * *
* * *
* *
* G F G *
* *
* *
* *
* *
* *
* *
* Approach :
The following steps are used :
- Form the worksheet of n X n+1 using two loops.
- Apply the if-else conditions for printing stars.
- Apply the if-else conditions for printing text "GFG".
- Apply else condition for rest spaces.
Note: The value of n must be greater than 8
Below is the implementation of the above approach :
# define size n = even only
n = 8
# so this heart can be made n//2 part left,
# n//2 part right, and one middle line
# i.e; columns m = n + 1
m = n+1
# loops for upper part
for i in range(n//2-1):
for j in range(m):
# condition for printing stars to GFG upper line
if i == n//2-2 and (j == 0 or j == m-1):
print("*", end=" ")
# condition for printing stars to left upper
elif j <= m//2 and ((i+j == n//2-3 and j <= m//4) \
or (j-i == m//2-n//2+3 and j > m//4)):
print("*", end=" ")
# condition for printing stars to right upper
elif j > m//2 and ((i+j == n//2-3+m//2 and j < 3*m//4) \
or (j-i == m//2-n//2+3+m//2 and j >= 3*m//4)):
print("*", end=" ")
# condition for printing spaces
else:
print(" ", end=" ")
print()
# loops for lower part
for i in range(n//2-1, n):
for j in range(m):
# condition for printing stars
if (i-j == n//2-1) or (i+j == n-1+m//2):
print('*', end=" ")
# condition for printing GFG
elif i == n//2-1:
if j == m//2-1 or j == m//2+1:
print('G', end=" ")
elif j == m//2:
print('F', end=" ")
else:
print(' ', end=" ")
# condition for printing spaces
else:
print(' ', end=" ")
print()
Output:
* * * *
* * * *
* * * *
* * *
* *
* G F G *
* *
* *
* *
* *
* *
* *
*
Time complexity: O(n2) for given input n
Auxiliary Space: O(1)
