Select any row from a Dataframe using iloc[] and iat[] in Pandas
Last Updated :
23 Aug, 2021
Improve
In this article, we will learn how to get the rows from a dataframe as a list, using the functions ilic[] and iat[]. There are multiple ways to do get the rows as a list from given dataframe. Let’s see them will the help of examples.
import pandas as pd
# Create the dataframe
df = pd.DataFrame({'Date':['10/2/2011', '11/2/2011', '12/2/2011', '13/2/11'],
'Event':['Music', 'Poetry', 'Theatre', 'Comedy'],
'Cost':[10000, 5000, 15000, 2000]})
# Create an empty list
Row_list =[]
# Iterate over each row
for i in range((df.shape[0])):
# Using iloc to access the values of
# the current row denoted by "i"
Row_list.append(list(df.iloc[i, :]))
# Print the first 3 elements
print(Row_list[:3])
Output:
[[10000, '10/2/2011', 'Music'], [5000, '11/2/2011', 'Poetry'],
[15000, '12/2/2011', 'Theatre']
Using iat[] method -
# importing pandas as pd
import pandas as pd
# Create the dataframe
df = pd.DataFrame({'Date':['10/2/2011', '11/2/2011', '12/2/2011', '13/2/11'],
'Event':['Music', 'Poetry', 'Theatre', 'Comedy'],
'Cost':[10000, 5000, 15000, 2000]})
# Create an empty list
Row_list =[]
# Iterate over each row
for i in range((df.shape[0])):
# Create a list to store the data
# of the current row
cur_row =[]
# iterate over all the columns
for j in range(df.shape[1]):
# append the data of each
# column to the list
cur_row.append(df.iat[i, j])
# append the current row to the list
Row_list.append(cur_row)
# Print the first 3 elements
print(Row_list[:3])
Output:
[[10000, '10/2/2011', 'Music'], [5000, '11/2/2011', 'Poetry'],
[15000, '12/2/2011', 'Theatre']]
