Quartiles | Formula, Definition and Solved Examples

Quartiles divide a data set into four equal parts, each containing 25% of the data. They help to understand the spread and center of the data. As an important concept in statistics, quartiles are used to analyze large data sets by highlighting values near the middle. This method is particularly useful for identifying outliers and comparing different data sets.

There are three quartiles:

Lower or First Quartile (Q₁)

• Quartile 1 lies between the starting term and the middle term.
• This is the median of the lower half of the data set.
• It is also known as the 25th percentile because it marks the point where 25% of the data is below it.

Median or Second Quartile (Q₂)

• Quartile 2 lies between the starting terms and the last terms, i.e., the Middle term.
• This is the median of the entire data set.
• It is also known as the 50th percentile, as it divides the data into two halves.

Upper or Third Quartile

• Quartile 3 lies between quartile 2 and the last term.
• This is the median of the upper half of the data set.
• It is also known as the 75th percentile because it marks the point where 75% of the data is below it.

Quartile Formula

As mentioned above, Quartile divides the data into 4 equal parts. There is a separate formula for finding each quartile value, and the steps to obtain the quartile formula are as shown below as follows: 

Step 1: Sort the given data in ascending order.

Step 2: Find respective quartile values/terms as per need from the below formulae.

• First Quartile = \frac{(n + 1)}{4} \text{\small th term}
• Second Quartile = \frac{(n + 1)}{2} \text{\small th term}
• Third Quartile = \frac{3(n + 1)}{4} \text{\small th term}

Where n is the total number of values in the dataset.

Let's understand the topic better with a solved example.

For Example: Find the Q₁, Q₂, and Q₃ of the given dataset: 3, 5, 7, 8, 10, 11, 3, 1, 1, 11.

Solution:

Arrange the dataset in ascending or descending order, depending on your preference. We will arrange the data in ascending order: 1, 3, 3, 5, 7, 8, 10, 11, 11

Cut the list into Quarters: (n = number of terms)

• Quartile 1 (Q1) = [(n + 1)/4] ^th Term = [( 9+ 1) / 4] = 2.25 term [Rounds off to 3 term] = 3
• Quartile 2 (Q2) = [(n + 1)/2 ] ^th Term = [{9 + 1)/2] = 5 ^th Term = 7
• Quartile 3 (Q3) = [3(n + 1)/4 ] ^th Term = [3 (10 + 1)/4] ^th Term = 7.5 ^th Term [Rounds off to 8 ^th Term] = 11

Quartiles in Statistics

We know that the Median divides the data into two equal parts; in the same way, the quartile divides the data into four parts. Similar to the median, which divides the data into half so that 50% of the data lies below the median and 50% lies above it, the quartile splits the data into, i.e..

• First Part: From smallest to largest of numbers, 25% of the value comes under this part ,and also this part lies below the first quartile.
• Second Part: Value between 25% and 50% of the data comes under this part, and this part lies between the first and second quartile (Median).
• Third Part: Value between 50% and 75% of the data comes under this part, and this part lies between the second and third quartile.
• Fourth Part: The Greatest 25% of all values in the data comes under the fourth part, and this part lies above the fourth quartile.

In the chart, the continuous variable is plotted against the independent variable, and the data is divided into quartiles.

Generalized Formula for Quartile

The generalized formula for the quartile is,

\bold{\text{Quartile}_r = l_1 + ( i\cdot \frac{n}{4} - c_f) \cdot \frac{(l_2-l_1)}{f}}

Where,

• Quartile_r indicates r^th quartile,
• l₁, l₂ are the lower and upper limit value that contains the i^th quartile,
• f is the frequency count,
• c_f is the cumulative frequency of the class preceding the quartile class.

Using this generalized formula, the first and third quartiles can be calculated as:

• \bold{\text{Q}_1 = l_1 + ( \frac{n}{4} - c_f) \cdot \frac{(l_2-l_1)}{f}}
• \bold{\text{Q}_3 = l_1 + ( \frac{3n}{4} - c_f) \cdot \frac{(l_2-l_1)}{f}}

Interquartile Range

Interquartile Range is the distance between the first quartile and the third quartile. It is also known as a mid-spread. It helps us to calculate variation for the data, which is divided into quartiles. The formula for calculating the Interquartile range is given by,

Interquartile Range (IQR) = Q₃ - Q₁

Where, 

• Q₃ is the third/upper quartile, and 
• Q₁ is the first/lower quartile.

Quartile Deviation 

Quartile Deviation is defined as half of the distance between the first quartile and the third quartile. It is also known as the semi-interquartile range. The formula for quartile deviation is given by,

Quartile Deviation = (Q₃ - Q₂)/2

Quartile vs Percentile

The key differences between Quartile and Percentile are given as follows:

Articles related to the Quartile Formula

• Central Tendency
• Mean
• Mode

Solved Problems on Quartiles

Problem 1: Find Quartile 1 for the given data: 10, 30, 5, 12, 20, 40, 25, 15, 18.

Solution:

Step 1: Sort the given data in ny order ( ascending order / descending order) 
5, 10, 12, 15, 18, 20, 25, 30, 40

Step 2: Find 1st Quartile
FIrst Quartile = (\frac{n + 1}{4})^{th}           term

Here n = 9 because there are total 9 numbers in the given data.
⇒ First Quartile = ((9 + 1)/4)^th term
⇒ First Quartile = (10/4)^th term
⇒ First Quartile = 2.5^th term

Now, 2.5^th term = 2nd term + (0.5) (3^rd term - 2^nd term)
⇒ 2.5^th term = (10) + (0.5) (12 - 10)
⇒ 2.5^th term = 10+1 
⇒ 2.5^th term = 11

The First Quartile value is 11.

Problem 2: Find the Second Quartile for the data 10, 30, 5, 12, 20, 40, 25, 15, 18.

Solution:

Step 1: Sort the given data in the ascending order

5, 10, 12, 15, 18, 20, 25, 30, 40

Step 2: Find 2nd Quartile

Second Quartile = (\frac{n + 1}{2})^{th}           term

Here n = 9 because there are total 9 numbers in the given data.
⇒ Second Quartile = (\frac{9 + 1}{2})^{th}           term
⇒ Second Quartile = (10/2)^th term
⇒ Second Quartile = 5^th term
5^th term is 18

So the Second Quartile value is 18.

Problem 3: Find the third Quartile for the data 10, 30, 5, 12, 20, 40, 25, 15, 18.

Solution:

Step 1: Sort the given data in the ascending order
5, 10, 12, 15, 18, 20, 25, 30, 40

Step 2: Find 3^rd Quartile
Third Quartile = \frac{3(n + 1)}{4}^{th}    term

Here n = 9 because there are total 9 numbers in the given data.
⇒ Third Quartile = \frac{3(n + 1)}{4}^{th}     term
⇒ Third Quartile= \frac{3 \times (10)}{4}^{th}     term
⇒ Third Quartile= 7.5^th term

7.5^th term is average result of 7^th and 8^th term = (25 + 30)/2 = 27.5
Remember:  7.5^th term = 7^th term + (0.5) (8^th term - 7^th term)

The most recommended method to find value is mentioned above
Because the term not always N.5 something  it may vary from N.1 to N.9 
Here, N be any natural number.

So the third Quartile value is 27.5.

Problem 4: Find the first, second, and third quartiles for the data 8, 5,15,  20, 18, 30,  40, 25

Solution:

Step 1: Sort the given data in the ascending order

5, 8, 15, 18, 20, 25, 30, 40.

Step 2: Find all Quartiles step by step

First Quartile= {(n + 1)/4}^th term

Here n = 8 because there are total 8 numbers in the given data.

⇒ First Quartile = {(8 + 1)/4}^th term
⇒ First Quartile= {9/4})^th term
⇒ First Quartile= 2.25^th term

Thus, 2.25^th Term  = 2nd term + (0.25)(3^rd term - 2^nd term )

⇒ 2.25^th Term = 8+(0.25)(15-8) = 9.75

First Quartile value is 9.75

Second Quartile = {(n + 1)/2}^th term

⇒ Second Quartile = (9 + 1)/2}^th term
⇒ Second Quartile = {10/2}^th term
⇒ Second Quartile = 5^th term

5^th term is 20

So the second Quartile value is 20.

Third Quartile = 3(n + 1)/4^th term

⇒ Third Quartile = (3(8 + 1)/4)^th term
⇒ Third Quartile = (27/4)^th term
⇒ Third Quartile = 6.75^th term

Thus, 6.75^th  = 6th term +(0.75)(7th -6th)

⇒ 6.75^th = 25+ (0.75)(5)= 28.75

So the third Quartile value is 28.75

Problem 5: What is the Interquartile Range for the data if the first quartile is 10 and the third quartile is 30cm?

Solution:

Given,

• Q₁ = 10
• Q₃ = 30

Interquartile range = Q₃ - Q₁
⇒ Interquartile range = 30 - 10

Thus, Interquartile range is 20.

Problem 6: What is the Quartile Deviation for the data if the first quartile is 15 and the third quartile is 30cm?

Solution:

Given,

• Q₁ = 15
• Q₃ = 30

Quartile Deviation = (Q₃ - Q₁)/2

⇒ Quartile Deviation = (30 - 15)/2
⇒ Quartile Deviation = 15/2

Thus, Quartile Deviation is 7.5

Quartile Formula Question

Question 1: Given the dataset: 10, 30, 5, 12, 20, 40, 25, 15, 18, calculate Q1, Q2, and Q3.

Question 2: Annual salaries (in thousands) of 20 employees: 22, 25, 28, 29, 32, 34, 36, 37, 39, 41, 43, 45, 47, 50, 52, 54, 56, 59, 61, 63. Determine Q1, Q2, and Q3.

Question 3: Given the dataset: 3, 8, 12, 17, 20, 24, 27, 31, compute Q1, Q2, and Q3.

Question 4: Data points: 1, 2, 2, 3, 4, 4, 5, 5, 6, 7, 100. Identify Q1, Q2, and Q3 and discuss how the outlier affects the quartile values.

Question 5: Test scores of 15 students: 55, 60, 61, 63, 67, 69, 72, 75, 78, 81, 83, 85, 88, 90, 92. Calculate Q1, Q2, and Q3 and interpret the results to understand the spread and distribution of the students' test scores.

Conclusion

Quartiles are statistical values that divide a dataset into four equal parts, each representing 25% of the data. They are essential in understanding the spread and distribution of data, particularly in large datasets. Quartiles help in identifying the central tendency, dispersion, and outliers within a dataset. The three quartiles are the first quartile (Q1), which marks the 25th percentile, the second quartile (Q2) or median, which marks the 50th percentile, and the third quartile (Q3), which marks the 75th percentile.