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Current simplifications of 'x && 1 --> x' and its dual
'x || 0 --> x' are wrong because the '||' and '&&' operators
demand that their operands are first compared against zero
which then always give a boolean valued result.
For example: '3 && 1' is not equal to '3' but to '1' (or 'true').
The correct simplification is thus 'x && 1 --> x != 0' and
'x || 0 --> x != 0'.
Fix this by always first doing the comparison against zero
before generating the OP_AND_BOOL and OP_OR_BOOL instructions.
Note: of course, we could decide that the semantic of OP_AND_BOOL
and OP_OR_BOOL is that these ops take care themselves of
making a boolean context (which was, I think, why these
ops were created) but then these simplifications cannot be
done (or when they are done, we need to add the comparison
against zero).
Fixes: b85ec4bb7f5b1c522d7c71782dbd9cf1c4c49b2f
Fixes: a0886db12307d2633b04ec44342099a2955794a5
Signed-off-by: Luc Van Oostenryck <luc.vanoostenryck@gmail.com>
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